With generics, the metatype of a type variable is an interface type. If you just... | Hacker News

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		earthboundkid on Dec 15, 2021 \| parent \| context \| favorite \| on: Go Replaces Interface{} with 'Any' With generics, the metatype of a type variable is an interface type. If you just had T, it’s grammatically incomplete because you don’t specify the metatype. I guess you could just assume the any type if it’s incomplete, but that’s an unnecessary inconsistency in the grammar.

eweise on Dec 15, 2021 [–]

I don't know. Making constraints optional is the way it works in all the other languages I use.

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