Yes, the 'exact' answer is the tangent. If you want the relationship between K and Phi, then:
K = Cos(Phi) + SQR( (pi+phi)^2 - sin^2(phi))
The derivation of both of these is contained in the article.
Yes, the 'exact' answer is the tangent. If you want the relationship between K and Phi, then:
K = Cos(Phi) + SQR( (pi+phi)^2 - sin^2(phi))
The derivation of both of these is contained in the article.